Readers are advised to proceed with the construction of the presented circuits only after understanding the concepts from the core. Not adhering to this can lead to failures and frustrations.

Search This Blog

Loading...

Tuesday, October 2, 2012

Automatic 40 Watt LED Solar Street Light Circuit Project - Part-1

Today solar panels and PV cells have become very popular and in the near future we would possibly see everyone of us using it in some or the other way in our life. One important use of these devices has been in the field of street lighting. The following article discusses one such interesting circuit which comprehensively explains the making of a 40 watt fully automatic solar street light system circuit (exclusively designed by me).


The circuit which has been discussed here has most of the standard specifications included with it, the following data explains it more elaborately:


LED Lamp Specifications

Voltage: 12 volts (12V/26AH Battery)

Current Consumption: 1.4 Amps @13 volts, and 1.2 Amps @12V

Power Consumption: 1.2 * 12 = 14.4 watts, (equivalent to light emitted by 39 watt LED lamp)

Light Intensity: Approximately around 2000 lm(lumens)

Charger/Controller Specification

Input: 32 volts from a solar panel specified with around 32 volts open circuit voltage, and short circuit current of 5 to 7 Amps.

Output: Max. 14.3 volts, current limited to 4.4 Amps

Battery Full - Cut OFF at 13.98 volts (set by P2).

Low Battery - Cut OFF at 11.04 volts (set by P1).

Battery charged at C/5 rate with float voltage restricted to 13.4 volts after “battery full cut OFF”.

Automatic Day/Night Switching with LDR Sensor (set by selecting R10 appropriately).

In this first part of the article we will study the solar charger/controller stage and the corresponding over/low voltage cut-off circuit, and also the automatic day/night cut-off section.




Parts List

R1, R3,R4, R12 = 10k
R5 = 240 OHMS
P1,P2 =10K preset
P3 = 10k pot or preset
R10 = 470K,
R9= 2M2
R11 = 100K
R8=10 OHMS 2 WATT
T1----T4 = BC547
A1/A2 = 1/2 IC324
ALL ZENER DIODES = 4.7V, 1/2 WATT
D1---D3,D6 = 1N4007
D4,D5 = 6AMP DIODES
IC2 = IC555
IC1 = LM338
RELAYS = 12V,400 OHMS, SPDT
BATTERY = 12V, 26AH
SOLAR PANEL = 21V OPEN CIRCUIT, 7AMP @SHORT CIRCUIT.

Solar Charger/Controller, High/Low Battery Cut OFF and Ambient Light Detector Circuit Stages:

Referring to the circuit diagram above, the panel voltage is regulated and stabilized to the required 14.4 volts by the IC LM 338.

P3 is used for setting the output voltage to exactly 14.3 volts or somewhere near to it.

R6 and R7 forms the current limiting components and must be calculated appropriately as discussed HERE.

The stabilized voltage is next applied to the voltage/charge control  and the associated stages.

Two opamps A1 and A2 are wired with converse configurations, meaning the output of A1 becomes high when a predetermined over voltage value is detected, while the output of A2 goes high on detection of a predetermined low voltage threshold.

The above high and low voltage thresholds are appropriately set by the preset P2 and P1 respectively.

Transistors T1 and T2 respond accordingly to the above outputs from the opamps and activates the respective relay for controlling the charge levels of the connected battery with respect to the given parameters.

The relay connected to T1 specifically controls the overcharge limit of the battery.

The relay connected to T3 is responsible for holding the voltage to the LED lamp stage. As long as the battery voltage is above the low voltage threshold and as long as no ambient light is present around the system, this relay keeps the lamp switched ON, the LED module is instantly switched OFF in case the stipulated conditions are not fulfilled.


IC1 along with the associated parts forms the light detector circuit, its output goes high in the presence of ambient light and vice versa.

Assume it's day time and a partially discharged battery at 11.8V is connected to the relevant points, also assume the high voltage cut off to be set at 14.4V. On power switch ON (either from the solar panel or an external DC source), the battery starts charging via the N/C contacts of the relay.

Since it's day, the output of IC1 is high, which switches ON T3. The relay connected to T3 holds the battery voltage and inhibits it from reaching the LED module and the lamp remains switched OFF.

Once the battery gets fully charged, A1's output goes high switching ON T1 and the associated relay.

This disconnects the battery from the charging voltage.

The above situation latches ON with the help of the feedback voltage from the N/O contacts of the above relay to the base of T1.

The latch persists until the low voltage condition is reached, when T2 switches ON, grounding T1's base biasing and reverting the top relay into the charging mode.

In the NEXT ARTICLE we will discuss the PWM controlled, simple LED lamp module and find out how the above circuit is integrated with it.

137 comments:

  1. i dont want the led driver as load i just want to use this design as solar charge controller so what should i eliminate ? please help me

    ReplyDelete
    Replies
    1. Please refer the following circuit:

      http://homemadecircuitsandschematics.blogspot.in/2011/12/how-to-build-solar-panel-voltage.html

      Delete
  2. You have shown a Heat Sink, in the immage, i think you have left out a transistor part to be mentioned

    ReplyDelete
    Replies
    1. The heatsink is mounted over the IC LM338.

      Delete
  3. dear sir, i want use this circuit for 50 watt 230 volt load and i dont want the ldr circuit. plese suggest me.

    ReplyDelete
    Replies
    1. what is your load? is it AC or DC?

      For AC loads you will need an inverter.

      Delete
  4. 45 watt cfl. works on ac 230 ac volts. i dont want LDR circuit.please suggest me.

    ReplyDelete
    Replies
    1. Remove the IC555 and the associated parts for getting rid of the LDR switch circuit.

      Connect the points "to LED module" to inverter input supply.

      Delete
    2. dear sir , i am bala, i did the circuit without IC 555, iam not able to set the P1 and P2. please explain the alignment method. it will help to finish the project.

      Delete
    3. Dear Bala, For better indication replace the 1N4007 diodes a the outputs of A1 and A2 with LEDs.

      Now apply input voltage to the circuit, adjust P3 to generate 14.3V, and adjust P2 such that the LED at the output of A1 just lights up fully.

      Now reduce adjust P3 to get 11.2V and adjust P1 such that A2 LED now just lights up fully...........your circuit is set.

      Delete
    4. dear sir , As per your suggestions i did the alignment it is working fine and project is completed .but i cannot understand the battery full cut off area battery protection , T1 and its relay function. when i give 14.3 voltage to the circuit the charging voltage 13.3 comes to the battery . how the battery it is protected by over charging .

      with your help only i am doing all .

      please explain sir.

      thanks lot

      Delete
    5. OK, remove R8 if you want a complete cut off.....

      Delete
    6. ok sir , what is doing R8 in that place ,i cannot understand , please explain.


      the circuit is working well now.

      Delete
    7. R8 is for restricting the battery voltage from falling below 13V after it's been cut off from the charging mode...

      Delete
  5. ok i will post you after testing the circuit. thank u sir.

    ReplyDelete
  6. dear sir , please mention the R12 value

    ReplyDelete
  7. dear sir ,
    i have 230 vol a.c 600 va inverter and 12v/100 ah battery for my home to manage power cut. due to severe power cut iam planing to go for solar panels and charge controller. i want to charge my battery in solar panel at day time . here how i can change solar panel and a.c mains. i want to change my inverter ? please suggest me .

    ReplyDelete
    Replies
    1. You can try the circuit given in the following article, this circuit will charge your 100ah battery efficiently.

      http://homemadecircuitsandschematics.blogspot.in/2012/11/high-current-transistor-tip36-datasheet.html

      Delete
  8. dear sir ,
    iam going to make this circuit . please tell me where i want to place led for battery full(led green) and battery low (led red).

    ReplyDelete
    Replies
    1. across A1 output pin and ground with a 1K series resistor.

      Delete
  9. ok sir for battery low indication ?

    ReplyDelete
    Replies
    1. across A2 output and ground with 1K resistor.

      Delete
  10. thank u sir , i will give u feedback later.

    ReplyDelete
  11. Dear sir,

    What should I use for the opamp.Is it ok 7404.I cant understand how to use the opamp,s pins.pls help me.thanks.

    ReplyDelete
    Replies
    1. 7404 does not have opamps, as given in the parts list you should use LM324, which has four opamps, any two may be used out of them....

      Delete
  12. I want to increase the power to 3KVA.I have got 24-0-24V transformer about 5kA. I am intending increasing the FET to 16pcs WITH A HEAT SINK, instead of 2.What other changes should l make to the circuit to achieve the power of 3kVA.Thanks for all your efforts.-Ladipo K.O ,fut, Akure, Nigeria.

    ReplyDelete
  13. I need help to understand the use of this diode in this solar panel junction box. Purchased 25w 12v panel for some testing and found two diode attached in serial. Please help me to understand. I can take pic and upload if needed. thank you Swagatam for all your help.

    http://t0.gstatic.com/images?q=tbn:ANd9GcQJgYPA4xVui04EOka6sOw1Y_kq_xMjonVl0wOCxYDUrfg6SGhzvSZ-6aqP

    ReplyDelete
    Replies
    1. how is it connected, in parallel to the solar panel output or in series??

      Delete
    2. Hi Ram, these are Bypass diodes...please read the following post:

      http://www.oksolar.com/technical/diodes_in_pv_systems.htm

      Delete
  14. Its connected in parallel in output. Using above post I understand few something to avoid heating / short circuit by produced by the shaded cells.

    I had info about blocking diodes which we connect in series with battery. Thank you again

    ReplyDelete
    Replies
    1. the shaded cells act more negatively compared to the unshaded cells, which generates heat inside the shaded cells due to the formation of negative current.

      A bypass diode nullifies the negativity of the cells by allowing current through it and thereby avoiding the heating of the shaded cells.

      Delete
  15. sir , i did the circuit , it is working fine .sometimes the low voltage cut off relay giving vibration sound, i want to replace the relay ?

    ReplyDelete
    Replies
    1. yes, because A2 does have hysteriesis, do these modifications to solve the problem:

      Connect the non-inverting(+)pin of A2 to R2 via a 10K resistor.

      Next, connect another 100K resistor across the non-inverting(+)pin and the output pin of A2....this will hopefully solve the issue.

      Delete
    2. sir
      i did all. but little sound has come when the battery voltage is in 11.4 to 11.1 after that the load disconnected .

      Delete
    3. sorry sir , not solved .

      Delete
    4. sir , waiting for your response.

      Delete
    5. Can't diagnose it, because a resistor across the explained input and output pins should have stopped the chattering of the relay....

      Delete
  16. sorry sir , i did a mistake with non-inverting(+)pin of A2 to R2 via a 10K resistor. now it is working well(there is no sound when the low cut off time). perfectly working. thanks for your valuable co-operation.

    bala

    ReplyDelete
  17. hi sir i need a charge controller for solar street light please help me

    ReplyDelete
  18. sir how many hours its take to charge full battery and how many hours its lights and can we connect 60watt panel and above 12volt 26ah battery?? please help me?

    ReplyDelete
    Replies
    1. you can connect 60 watt panel and 12V 26 AH battery to this circuit.

      battery should get charged within 7 hours of full sunlight.

      Delete
  19. Res Sir,
    thanks for this precious circuit, I have made it using LM 338T (part no JM91BR) and gave an input of 17v from an solar panel of 12v 30 w rating. but when checking the volatge it is only 1.4v output, I think I've gone wrong some where, I've used a 5k preset intead of 4k7 preset, is it the problem, or else may be i've used a 220 ohms as R6 and 400 ohms R7, is my calculation wrong, can you tell me exactly what should be R6 and R7 to charge a 12v 26 Ah battery, because I am bad at calculation.Also can I use a LM317T for the same circuit to chagre a battery of 12v 7Ah x 2 in Parallel, please help me sir, thanking you once again
    Prem A

    ReplyDelete
    Replies
    1. use 10 K preset for P3. rest everything is OK.

      LM317 will not charge 2 X 7ah, it can charge only a single 7ah battery.

      Delete
  20. Thank you so much sir, I'll try and get back to you Thank you and Good Night

    ReplyDelete
  21. Res Sir,
    I tried your suggestion of replacing the 5K preset to 10k but the output still remains at 1.4v Please Help

    Prem

    ReplyDelete
    Replies
    1. then something's definitely wrong with your circuit (connections) or the IC.

      Delete
  22. I removed the 338 Ic and checked, it is giving an output equal to input, but back in the circuit it gives only 1.4 v do I ve check the BC 547 ic or the should I send the PCB Diagram I made for your consideration Sir, I designed it and asked one PCB Maker to etch it for me . Please ... waiting for your reply and also sorry for troubling you so much

    ReplyDelete
    Replies
    1. OK, remove the transistor and check, it might be faulty.

      Delete
  23. Good Evening sir. i just want to ask if what is the value of P3 and R9? is it really 4K7 or 47K ? and the 2M2 or 22M? thanks

    ReplyDelete
  24. I bought six solar garden lights from the store hoping they will illuminate my pathway and garden. However, these tiny chinese made solar lamps (it has one single 5mm led) produce only very little amount light like a firefly even with the full charge. Each lamp has only one 1.2v 600mah battery and the tiny solar cells are attached to the top of the lamp. On top of that I did not realize some parts of my garden get only 1 or 2 hours sunlight. Could you PLEASE help me to design a circuit that one solar panel (let say 3 to 5 watt) can safely (auto cut off when overcharges) charge some Li-ion 3.7v 3000maH (18650 type) or Sealed Lead Acid battery and then this power can be distributed to all 6 garden lamps to light high power LEDs (preferably 1W or 3W) in each lamp? I would greatly appreciate your invaluable time and effort to help me. My email address is mikbh@hotmail.com (please do NOT post my email address on this public domain, if you decide to publish this post). Thank you.
    With warmest regards,
    Mike

    ReplyDelete
    Replies
    1. Thanks!

      You can try the SECOND circuit shown in the following article.

      You can incorporate any battery between 3 and 12V as per your specs.

      http://homemadecircuitsandschematics.blogspot.in/2012/07/make-6v-4ah-automatic-battery-charger.html

      There's no edit facility here, so cannot remove your email ID....if you say I can permanently delete this conversation.

      Delete
  25. Also, I would like them to automatically turn on at dusk and turn off at dawn (like these tiny solar garden lamps do which have light sensor diodes but read somewhere that circuits made without these sensors to make dusk to dawn are better than with sensors, unfortunately, the author does not elaborate why).

    ReplyDelete
    Replies
    1. You may refer to the second circuit that's shown in the following post, it uses an LDR for the required detection which is probably a better option than photo-diodes:

      http://homemadecircuitsandschematics.blogspot.in/2012/08/led-emergency-light-circuit-with.html

      Delete
  26. I don't understand how you derived "Current Consumption: 1.4 Amps @13 volts, and 1.2 Amps @12V" on top of the page under the title LED Lamp Specifications. My understanding was 1watt led has 350mA current rating, that doesn't add up just the 1.2 or 1.4Amp, please teach me correct way of calculating.

    ReplyDelete
    Replies
    1. first of all here we are not driving the leds at full 350 mA, and is not recommended.

      the IC will generate pwm pulses which will keep the leds illuminated for only 50% of its total illumination period.

      therefore the effective consumption becomes 39/3(series) = 13 x 0.2(current) = 2.6amps/2(50%) = 1.3 amps.

      I hope you got it now.

      Delete
  27. Just for the curiosity, can I use high power 3 watt leds instead of 1 watt in this circuit since the Vf for both 1 watt and 3 watts are within your calculation to arrange 3 leds on series and if this idea of PWM utilize very low current to illuminate the leds, it should not be the problem (despite the full current for 3 watt led is 700mA)? If I can use 3 watt leds, is there anything I need to modify on the circuit? Thanks.

    ReplyDelete
    Replies
    1. Yes you may do it. No modifications would be required, the transistor might require a bigger heatsink though.

      Delete
  28. I want to know the rate of this finished product of yours. Kindly mail to my email id mohanrao_70@yahoo.com as well as other products which will be helpful for my own use.

    ReplyDelete
    Replies
    1. will it be on a regular basis (quantity) or just a single piece? because i won't be able to sell single units

      Delete
  29. hi
    i want to make a automatic solar charge controller for 12V 40ah lead acid battery having 9W load to operate. and i'm having panel of 18v 2.5A. please suggest me circuit my email jp8rock@gmail.com

    ReplyDelete
    Replies
    1. Hi,

      You may try the above explained circuit, the IC1 stage along with the lower relay, D2,R4,and T3 won't be required, they all may be eliminated..

      Delete
  30. Hello Sir what will be the cost of this complete project. kindly mail it to my id aier1990@gmail.com

    ReplyDelete
    Replies
    1. around Rs200/- or $4 excluding solar panel and battery.

      Delete
  31. can u tell me whats the value of capacitor across R10

    ReplyDelete
  32. Hello Sir
    I have a 40 watt solar panel and 12v,30AH battery and want to make this circuit, so can i used this ratings for this circuit.. looking forward for ua kind suggestion..

    ReplyDelete
    Replies
    1. Yes you may go ahead with it, it will work.

      Delete
    2. Thank you sir.
      Sir for the value of R6 the formula as u have given in other blog its 0.6/R6 = 1/10 battery AH

      That means for my 12v30Ah R6 will be 0.2ohm only? Sir i am a bit confused with it...

      Delete
    3. yes your answer is absolutely correct.

      Delete
    4. hello sir
      According to my battery AH i.e 30AH,after calculating R6=0.2ohm,since it s not availabe in the market, i tried 5 1ohm's in parallel also bt due to tolerance and all it used to cum around 0.6 ohm so i am so confused, is there any way to use R6??

      Delete
    5. sorry there's no other way to do it. putting a resistor is the only option.

      Delete
    6. Sir, I have connected everything as the above circuit except that instead of R6=0.2ohm(as i have mention in the above comment) i used R6=0.6ohm and when i try to make the output voltage to nearly 14.3volts by adjusting the P3 i can't make it less than 16volts or else p3 start burning, the input voltage from the panel is 19volts... Is that because of R6?
      please looking forward for your valuable sugestion....

      Delete
    7. that should not happen, there may be a big mistake somewhere, check the LM338 pinout connections.

      even without R6 (replaced with wire link)), the preset will never burn in any position.

      the voltage should vary right from 1.25 to the maximum level (19V)

      Delete
    8. Thank you sir, its coming. I think there was something wrong with the preset connection or preset itself, after i changed the preset with new one its coming as u said i.e from 1.25 to the maximum level (19V). I have some querry sir
      1) the o/p current is coming approx. 8Ampere, is it ok or it should be limit to 4 t0 5 Ampere, if so than how sir?
      2) As u have said "For better indication replace the 1N4007 diodes a the outputs of A1 and A2 with LEDs.Now apply input voltage to the circuit, adjust P3 to generate 14.3V, and adjust P2 such that the LED at the output of A1 just lights up fully", i did that sir but the Led doesn't light up at any point...
      3) The battery used to get charge from the charging circuit without connecting the other part i.e Ic724 part, but when i connect the battery does not charge at all...

      Delete
    9. Make the stages separately, first make the LM338 stage only, adjust R7 so that only the desired amount of current is allowed at the output.

      Next build the last circuit shown in the following link:

      http://homemadecircuitsandschematics.blogspot.in/2012/11/making-40-watt-led-emergency-tubelight.html

      I will explain how to proceed after you have built it.

      Delete
  33. Hello sir, can you please tell me where to connect the led indication for knowing whether the battery is charging or not?

    ReplyDelete
    Replies
    1. please refer to the following diagram:

      http://4.bp.blogspot.com/-mJfdYOcXCzs/UJ3VJD8ygFI/AAAAAAAABQw/_kGCNyHxiW4/s1600/smart%20battery%20charger%20circuit.png

      Delete
    2. can we use any LDR??

      Delete
  34. hi sir. wat is the voltage value of the capacitor?





    ReplyDelete
  35. sir,im working on mppt project
    kindly help me with the battery selection

    ReplyDelete
    Replies
    1. what is the rating of your solar panel? Battery rating will need to be calculated according to it.

      Delete
  36. This comment has been removed by the author.

    ReplyDelete
  37. i want to make a automatic solar charge controller for 12V 60ah lead acid battery having 60W load to operate. and i'm having panel of 150w. please suggest me circuit my email sunsolarpower2@gmail.com

    ReplyDelete
    Replies
    1. You can use the circuit shown in the above article, just remove the IC555 (green IC) from the design, and use the rest of the circuit for your application.

      Delete
  38. Thank you so much sir, I'll try and get back to you, Thank you

    ReplyDelete
  39. sir R6,R7 VALUE confused calculation please 60ah battery

    ReplyDelete
    Replies
    1. R7 = 0.6/6 = 0.1 ohms

      don't use R6, replace it with a wire link.

      Delete
    2. Thank you so much sir, I'll try and get back to you Thank you and Good Night

      Delete
  40. what type of led you are using in this article??

    ReplyDelete
  41. Thanks can we use lm 350 since its current rating is 3A

    ReplyDelete
  42. hi, i have a few questons.

    1. how many hours will the battery take to discharge completely if 40 LED's are used as in your circuit.
    2.Is R10 min LDR circuit a preset or fixed. if fixed can a preset be used and of what value???
    3. where are full/low battery and ambient light indicators are connected in schematic???

    ReplyDelete
    Replies
    1. With a 26ah good condition battery it will take around 10 hours to discharge.

      R10 can be replaced with a 1M fixed resistor.

      Delete
    2. I'll update the circuit soon with the LED indicators.

      Delete
  43. Sir how to adjust p1 and p2 values nd my battery is of 18ah so what will b value of R7

    ReplyDelete
    Replies
    1. apply 14V to the circuit adjust p1 such that the top relay just activates.

      Now reduce voltage to 11V and adjust P2 such that the above relay just deactivates.

      Delete
  44. i used lm 350 bt the output is low
    hw to adjust the output in the voltage regulator

    ReplyDelete
    Replies
    1. sir, this circuit connection couplet, 555 ic section not work, battery low full position confuse led o/p relay not work help me

      Delete
  45. sir, i am siva the circuit connection complet.
    555 ic section not work, led o/p relay not work what my mistake

    ReplyDelete
  46. sir circuit connection complet, 555ic section not work, p1 p2 alinment confused, led relay not work, help me

    ReplyDelete
    Replies
    1. can you bring the circuit to me, i'll show you what faults you have made....

      Delete
  47. sir circuit connection couplet, 555ic section not work , p1 p2 aliment confused , led relay not work help me what my mistake

    ReplyDelete
  48. Replies
    1. use 1M for R10 and then focus some light on the LDR, check the the output LED response.

      Delete
  49. sir, 13.98v battery full, 11.04 low which is the pin aliment, 1m r10 focus light LDR 4.89v come change the relay. ldr set the PCB and near led so light distrupe?

    ReplyDelete
    Replies
    1. adjust P3 to get 11v across D5 cathode and ground. then adjust P2 to activate the upper relay.

      then adjust P3 to increase voltage to 14V, then adjust P1 to deactivate the upper relay and activate the lower relay.

      Delete
  50. can lm396 be used in place of lm338. it supply 10 ampere

    ReplyDelete
  51. lm338 is not available in my area. any 15v 5a supply will be fine i guess in place of lm338

    ReplyDelete
  52. ic 324 have 4 comparator in one ic can single ic be used???

    ReplyDelete
  53. you forgot to mention value of C1 capacitor

    ReplyDelete
  54. Dada
    Ic 324 consists of 4 gates and 14 pin so in the circuit can we use a single IC 324 for the complete purpose of the circuit.
    Tanmoy

    ReplyDelete
  55. lm 338 was not available so i used lm7815 with transistor d1047 (connecting input of 7815 to collector, output to base)for current more than just 1 A(output from 7815). is this arrangement ok???
    secondly how much max current can bc547 can pass??? can i use d1047 in place of bc547 if bc547 cannot supply current upto 2.5 A? if yes then what other changes do i need to make.

    ReplyDelete
    Replies
    1. where do you want to use BC547?

      BC547 can handle only upto 100mA

      Delete
  56. can i know if this circuit is working

    ReplyDelete
  57. Hello dada,
    I want to make this circuit as a emergency light for my village house because of huge power cuts.
    I had also made a semi automatic solar charger Iam uploading its image on facebook.
    and how can we modify this circuit to so that is charges the battery via the solar panel and it switch on the LED bank when the grid power supply fails and the sun goes down.
    (I think the concept which I used in my LED Emergency light transistor BD140,can work and power it by Transformer less power supply ).
    Can You explain how the IC 324 works?
    please help
    Thanks,
    Tanmoy

    ReplyDelete
    Replies
    1. Hello Tanmoy,

      You can use the above circuit for your application with the following modifications:

      Remove the IC2 section entirely and connect the D6 anode with D5 cathode.

      That's all is required rest all will be as is, the circuit will start functioning as per your specifications.

      Delete
    2. thanks dada for your quick reply.

      Delete
  58. I want to use this circuit as a college project but i need to finish it and put it in a reasonable cover and hence its a street light i was wondering if it will be possible to put the battery somewhere in the head of the street light

    Also is it possible to get a small solar panel that will give me the required 14.4V i need to charge the battery

    Thank you

    ReplyDelete
    Replies
    1. The battery can be installed anywhere around the light box, but should be appropriately enclosed and protected from water and direct sunlight.

      The desired soar panel can be easily procured from your nearby electronic market.

      Delete
  59. Thank you, will get in touch as i progress along

    ReplyDelete
  60. my ratings are 12v 5 watts solar pannel and battery is 12v 1.3 ah will this circuit can be made with this ratings? if not suggest me the appropriate ratings for low power (5-10 watts)

    ReplyDelete
    Replies
    1. the above circuit can be used with the specified components

      Delete

Readers are requested not to include external links while commenting. For consulting a diagram, upload it on Google Drive and provide the link here.