Tuesday, October 16, 2012

Designing a Grid-Tie Inverter Circuit

A grid tie inverter works quite like a conventional inverter, however the power output from such inverter is fed and tied with the AC mains from the utility grid supply. As long as the mains AC supply is present, the inverter contributes its power to the existing grid mains supply, and stops the process when the grid supply fails.

The concept is indeed very intriguing as it allows each of us to become an utility power contributor. Imagine each house getting involved in this project to generate overwhelming amounts of power to the grid, which in turn provides a passive income source to the involved residences. Since the input is derived from the renewable sources, the income becomes absolutely free of cost.

Making a grid tie inverter at home is considered to be very difficult as the concept involves some strict criteria to be observed, not following may lead to hazardous situations.

The main few things that must be observed are:

The output from the inverter must be perfectly synchronized with the grid AC.

The output voltage amplitude and frequency as mentioned above must all correspond with the grid AC parameters.

The inverter should switch OFF instantly in case the grid voltage fails.

In this post I have tried to present a simple grid-tie inverter circuit which according to me takes care of all the above requirements and delivers the generated AC into the grid safely without creating any hazardous situations.

Let's try to understand the proposed design (exclusively developed by me) with the help of the following points:

 Again, as usual our best friend, the IC555 takes the center stage in the entire application. In fact only because of this IC the configuration could become apparently so very simple.

Referring to the circuit diagram, the IC1 and IC2 are basically wired up as a voltage synthesizer or in a more familiar terms a pulse position modulators.

A step down transformer TR1 is used here for supplying the required operating voltage to the IC circuit, and as well as for supplying the synchronization data to the IC, so that it can process the output in accordance with the grid parameters.

Pin#2 and pin#5 of the both the ICs are connected to the point after D1, and via T3 respectively, which provides the frequency count and amplitude data of the grid AC to the ICs respectively.



The above two information provided to the ICs prompts the ICs to modify their outputs at the respective pins in accordance with these information.

The result from the output translates this data into well optimized PWM voltage that's very much synchronized with the grid voltage.

IC1 is used for generating positive PWM, while IC2 produce negative PWMs, both work in tandem creating the required push pull effect over the mosfets.

The above voltages are fed to the respective mosfets, which effectively converts the above pattern into a high  current fluctuating DC across the involved step up transformer input winding.

The output of the transformer converts the input into a perfectly synchronized AC, compatible with the existing grid AC.

While connecting the TR2 output with the grid, connect a 100 watt bulb in series with one of the wires. If the bulb glows, means the ACs are out of phase, reverse the connections immediately and now the bulb should stop glowing ensuring proper synchronization of the ACs.




Assumed PWM Waveform (bottom trace) at the Outputs of the ICs




Parts List

All resistors = 2K2
C1 = 1000uF/25V
C2,C4 = 0.47uF
D1,D2 = 1N4007,
D3 = 10AMP,
IC1,2 = 555
MOSFETS = AS PER APPLICATION SPECS.
TR1 = 0-12V, 100mA
TR2 = AS PER APPLICATION SPECS
T3 = BC547
INPUT DC = AS PER APPLICATION SPECS.

WARNING: THE IDEA IS BASED SOLELY ON IMAGINATIVE SIMULATION, VIEWERS DISCRETION IS STRICTLY ADVISED.


After receiving a corrective suggestion from one of the readers of this blog Mr. Darren and some contemplation, it revealed that the above circuit had many flaws and it wouldn't actually work practically.

The revised design is shown below, which looks much better and a feasible idea.

Here a single IC 556 has been incorporated for creating the PWM pulses.
One half of the IC has been configured as the high frequency generator for feeding the other half IC which is rigged as a pulse width modulator.

The sample modulating frequency is derived from TR1 which provides the exact frequency data to the IC so that the PWM are perfectly dimensioned in accordance with the mains frequency.

The high frequency makes sure the output is able to chop the above modulation information to precision and provide the mosfets with an exact RMS equivalent of the grid mains.

Finally, the two transistors make sure that the mosfets never conduct together rather only one at a time, as per the mains 50 or 60 Hz oscillations.




Parts List

R1,R2,C1 = select to create around 1 kHz frequency

R3, R4,R5,R6 = 1K

C2 = 1nF

C3 = 100uF/25V

D1 = 10 amp diode

D2, D3, D4, D5 = 1N4007

T1, T2 = as per requirement

T3, T4 = BC547

IC1 = IC 556

TR1, TR2 = as suggested in the previous section design

The above circuit was analyzed by Mr. Selim and he found some interesting flaws in the circuit. The main flaw being the missing negative PWM pulses of the AC half cycles. The second fault was detected with the transistors which did not seem to isolate the switching of the two mosfets as per the fed 50 Hz rate.

The above idea was modified by Mr. Selim, here are the waveform details after the modifications. modifications:

Waveform Image:



CTRL is the 100 Hz signal after the rectifier, OUT is from PWM from both halve waves, Vgs are the gate voltages of the FETs, Vd is the pickup on the secondary winding, which in sync with CTRL/2.

Disregard the frequencies as they are incorrect due low sampling speeds (else it gets too slow on the ipad). At higher sampling freqs (20Mhz) the PWM looks quite impressing.

To fix the duty cycle to 50% at around 9kHz, I had to put a diode in.

Regards,
Selim


For enabling the detection of the negative half cycles, the control input of the IC must be fed with both the half cycles of the AC, this can be achieved by employing a bridge rectifier configuration.

Here's how the finalyzed circuit should look according to me. The transistor base is now connected with a zener diode so that would hopefully enable the transistors to isolate the mosfet conduction such that they conduct alternately  in response to the 50 Hz pulses at the base T4.



Recent  Updates from Mr. Selim


Hello Swags,

I keep reading your blogs and continue experimenting on the breadboard.
I have tried the zener-diode approach (no-luck), CMOS gates and, much better, op-amps worked best. I've got 90VAC out of 5VDC and 170VAC from 9VDC at 50Hz, I believe it's in sync with the grid ( can't confirm as no oscilloscope). Btw the noise goes if you clamp it with a 0.15u cap. on the secondary coil.

As soon as I put a load on the secondary coil, it's voltage drops to 0VAC with only a slight increase in input DC amps. The Mosfets don't even try to draw more amps. Perhaps some mosfet drivers like IR2113 (see below) could help?

Although in high spirits, I feel that PWM might not be as straight forward as hoped. It definitely is good to control torque on dc motors at low pwm freqs. However when the 50 Hz signal gets chopped at higher freq, it for some reason looses power or the PWMd mosfet can't deliver the needed high amps on the primary coil to keep the 220VAC going under load.

I've found another schematic which is very closely related to yours, except PWM. You might have seen this one before.

The link is on http://www(dot)electro-tech-online(dot)com/alternative-energy/105324-grid-tie-inverter-schematic-2-0-a.html



The power handling circuit is an H drive with IGBTs (we could use mosfets instead). It looks like it can deliver the power across.

It looks complicated but actually is not too bad, what do you think? I will try to simulate the control circuit and let you how it looks.

Regards,


Selim

Sent from my iPad



111 comments:

  1. Hi Swagatam,

    what is the perfect TR2 and MOSFETS to use in this circuit?

    if i have a 12-0-12 1500watts transformer, how many FETS will i use for iRFZ44n?

    Regards,

    ReplyDelete
    Replies
    1. I would suggest you to first check whether the circuit works proposed in the explanation, if it does then you can proceed with the selection of the other sections like mosfets etc.

      By the way any type of N mosfet should work here, just make sure they are accurately matched with the transformer primary rating.

      Delete
    2. is this the circuit that can lower your electric bill?

      Regards,

      Delete
    3. No this circuit will not lower your electric bill, but in countries where production and selling of excess electricity is allowed, this type of inverters can become a source of passive income.

      Delete
    4. what is the Grid-Tie inverter that i saw in you tube that the meter runs in backward? is it true or just a joke?

      Delete
    5. I haven't tried this circuit practically so have no idea how it would respond...

      Delete
    6. can i use 500mA for TR1?

      Delete
    7. Hi
      You can get H bridge modules with the built in drivers and automatic dead time

      Regards
      Snuf

      Delete
  2. hi swagatam this is kurush karanjia here. This circuit of yours can be very help full in the PCU i am trying to make by synchronizing inverter output to the AC mains output and then suppling to loads. So please help and tell me how can i implement this circuit in the way i want.

    ReplyDelete
    Replies
    1. Hi Kurush,

      as mentioned in the bottom warning message, the idea has not been tested practically.

      So you will have to check it practically using an oscilloscope and other equipment to confirm its working.

      If the IC responds just as mentioned in the article then our job is done, we can be sure of the results.

      Delete
  3. thanks swagatam but some changes will have to be made to use it to supply load by synchronizing inverter and mains. so what changes will have to be made?

    ReplyDelete
    Replies
    1. I have assumed the IC to handle a few things which have been mentioned in the article, if that happens correctly rest of the things will automatically shape up.

      Synchronizing phase amplitude and frequency are the only things which are important. And also the inverter should switch OFF when mains is not available. All these things have been taken are of in the above circuit.

      Unless the circuit is tested practically nothing can be said.

      Delete
  4. here you have shown how to supply the power back to grid after synchronization but i dont wanna supply back to the grid i want to synchronize both the supplies and then supply the load from it

    ReplyDelete
    Replies
    1. OK, by synchronization you mean you want the inverter AC to replace the mains AC immediately when mains AC fails? Right?

      Delete
    2. no by synchronization i mean i want to synchronize the output of inverter and the ac mains and then supply to load when the inverter is not able to supply the load completely..

      Delete
    3. Yes i have tried to design exactly that in the above circuit, the ICs synchronizes the inverter AC output with the grid AC so that both merge together adding up the overall power to the appliances.

      Delete
    4. so please tell what should be the values of T2, mosfets and how much dc input should i use

      Delete
    5. T2 = BC547

      mosfet = sk1058

      please be cautioned: you are taking a huge risk by making something which has not been confirmed, and it involves potentially dangerous AC currents.

      Delete
    6. ok no problem i will take all possible precautions and will use a mcb before this entire device
      And i will be directly using the inverter output so which part of the circuit should i eliminate and where to collect the load

      Delete
    7. and what should be the values of the TR2

      Delete
    8. i think by mistake you have replied to this question in another post but its ok i got what you said but my question now is that i am gonna use the inverter output directly so will need to eliminate some portion of this circuit so what portion should i eliminate...?

      Delete
    9. This circuit cannot be used like a normal inverter because for that we may have to eliminate a few stages and also introduce additional new stages.

      You may refer to this circuit for making a simple inverter:

      http://homemadecircuitsandschematics.blogspot.in/2012/09/mini-50-watt-mosfet-inverter-circuit.html

      Delete
    10. i am gonna make the inverter using another circuit and then want to synchronize the output of that inverter with ac mains and then supply to loads

      Delete
  5. i will try making this at home so please tell what should be the values of T2, mosfets and how much dc input should i use

    ReplyDelete
    Replies
    1. The above circuit is of a grid tie inverter, I don't think you are looking for a grid-tie inverter circuit......???

      Delete
  6. The meter will run in the reverse if being fed.
    I have seen grid tie inverter and they have a complex a/c synchronization ic circuit and they work in a range of the ac voltage.
    Does this circuit also have a working voltage for the grid a/c and also frequency since frequency might drop due to heavy loads being used

    ReplyDelete
    Replies
    1. As per my assumptions, the above circuit derives the frequency and the amplitude information from the existing AC grid input and processes the circuit output accordingly, therefore the circuit should be producing perfectly synchronized AC back to the grid.

      Delete
    2. Thanks but is there any issue w.r.t grid voltage fluctuations

      Delete
    3. The inverter output will follow the grid voltage data accurately so there should not be any issues.

      Delete
  7. Hi Swagatam,

    what is the type of capacitors C2,C4?

    Regards,

    ReplyDelete
  8. Hi Swagatam,

    10amps diode is not available in my area. only 6amps. can i use it?

    Regards,

    ReplyDelete
  9. Hi Swagatam,


    i almost finish with the first circuit but suddenly you modified it, what is wrong with the first circuit?
    what is the function of BC547 in the modified circuit?

    i would like to know the T1 and T2, is it the same value of FET's?

    the T1 Source is connected to T2 Drain?

    Regards,

    ReplyDelete
    Replies
    1. I keep modifying my circuits to improve them more.

      Both the ICs should produce waveforms in tandem by translating both the halves of the grid AC cycles, therefore BC547 is added so that the bottom IC is able to translate the negative half cycles into the required PWM.

      T1 and T2 are same.

      "sources" are made common and connected to ground, and the drains are connected to the transformer taps.

      Delete
    2. thanks Swagatam for your quick response...

      i just want to clarify the connection of the FET's. because in the diagram my understanding the source and the drain is connected.

      i can put the FET's and parallel it into one heatsink?

      for testing purposes, can i use a lower wattage for a light bulb?

      Regards,

      Delete
    3. Yes in the diagram it's wrongly shown, the source should be made common and connected to ground.

      A common heatsink can be used for T1/T2

      low wattage bulb can be used for testing, but without oscilloscope you cannot judge the waveforms.

      Regards.

      Delete
    4. Hi Swagatam,

      it is not sure if the wave form is sine wave even if it is tested with the light bulb?

      what will happen if it is not synchronized with the local power?

      i already finished with this circuit and i don't have a oscilloscope.

      Regards,

      Delete
    5. First test the inverter separately, do not connect the output of the inverter to the grid, instead connect the output to a 100 watt bulb, next connect a DC power source may be a battery 25AH 12Vand to the shown points, check the bulb illumination.


      TR1 must be connected to the AC mains as shown for the above testing.

      If the bulb illuminates fully then we can proceed further.




      WARNING: THE SUGGESTIONS ARE BASED SOLELY ON MY IMAGINATIVE SIMULATION.....

      Delete
    6. can i use DM for testing the output?

      Delete
    7. with DMM you cannot check RMS and amplitude....

      Delete
  10. Hi Swagatam,

    i want to clarify the testing procedure.

    While connecting the TR2 output with the grid, connect a 100 watt bulb in series with one of the wires. If the bulb glows, means the ACs are out of phase, reverse the connections immediately and now the bulb should stop glowing ensuring proper synchronization of the ACs.

    - is TR1 connected to the grid?
    - do i need to connect the battery?

    Regards,

    ReplyDelete
    Replies
    1. TR1 is connected to the grid so that the 555 circuit is able to assess and the synchronize the waveform accordingly.

      Battery is required at the shown DC source points.

      Pls read the warning message at the end of the article.

      Delete
    2. so it is not sure if the testing of this circuit will run and safe?

      how do i test the wave form? on which point do i connect the probe?

      Regards,

      Delete
    3. It seems you are very much new in the field so I will recommend not to build this circuit, it may be dangerous for you.

      The output from TR2 can be fed to an oscilloscope to read the waveforms.

      Delete
  11. What kind of simulation tool did you use?
    Thank you

    ReplyDelete
  12. Seems that pin 7 cannot go to + or it will short.

    ReplyDelete
    Replies
    1. OK, thanks, you may add a 1K resistor in series with it.

      Delete
    2. Hi Swagatam,

      the 1K resistor is going to the positive of the battery?

      pin#4,6,7&8 of IC1,2 will put a 1K resistor going to the +?

      Regards,

      Delete
    3. No, the 1K resistors will go from pin#7 to the postive of the respective ICs (pin#4/#8....)

      Delete
    4. Ok i got it... thanks

      Delete
    5. Hi Swagatam,

      What about the pin#6?

      Delete
    6. yes both of them should be connected to the 1K resistor.. since they are both joined together...

      Delete
    7. Hi Swagatam,

      just for clarification...

      pin# 6 and 7 with 1K resistor will connect to pin# 4 and 8? or is it going to the + of the Battery?

      Regards,

      Delete
    8. pin#6 and 7 with 1K resistor will connect to pin# 4 and 8....NOT to the positive of the battery.....

      Regards.

      Delete
  13. Hi Swagatam,
    Been following this post for a while now and cannot beleive the amount of novice`s trying to build this un-tested project with no idea of what the components are doing. Do some research guys before you kill yourselfs.

    Looked at the circuit myself and I can understand the half wave entering the chip at pin 5 which will follow the mains frequency but cannot see what you are trying to do with pin 2 as this is also at the same frequency.

    You state that the chip is wired as a pulse position modulator which would be fine if it had another higher frequency either injected into pin 2 plus a timing cap or simply ocilating the chip at a higher frequency.

    The tall and short of this is where is the higher frequency derived from other than the 50/60Hz that is injected ?.

    Regards Darren.

    ReplyDelete
    Replies
    1. Hi Darren,

      I have already provided the necessary warning in the article and during the conversations.

      Yes pin#2 needs a high frequency for enabling the PWMs at the output.

      I'll reconsider the design soon and hopefully correct it.

      Thanks!

      Delete
  14. Hi Swagatam,

    Having done some more research about the 555 timer chip it seems you would have problems with the duty cycle only operating from 10%-90% which could cause both outputs to be on at once.

    I am thinking that a better aproach to this problem would be op-amps.

    Using something like a LM324N, 2 op-amps creating a high frequency saw-tooth and fed to the neg of the remaining two op-amps then half waves (50/60Hz) fed to the positive of the op-amps creating two seperate pwm outputs.

    Maybe this would be a easier option and only one chip to buy. All off the top of my head at the moment !!!.

    Hope this may help. Good Luck !.

    Regards, Darren.

    ReplyDelete
    Replies
    1. Hi Darren,
      Thanks!

      Yes surely opamps can be used also as suggested by you, but since I have already done some hard work in studying IC555, in my new design I employed them yet again, and hopefully eliminated the previous issues in this design.

      I have presented the revised design in the above article, I hope this time you won't have any trouble with it :)

      Regards.

      Delete
    2. Hi Swagatam,

      Good work!

      The circuit is shaping up to be a buildable project of which I might even have a go at for my 100w turbine. MANY THANKS!.

      Only one error i can see is that T3 and T4 emitters I reckon should go to the low voltage earth point and not the LIVE mains section.

      Keep up the good work and thanks again.

      Regards Darren.

      Delete
    3. Hi Darren,

      Thanks for correcting the diagram yet again, indeed it was a silly mistake from my part, I have corrected it now.

      Thank you for making this happen!

      Delete
  15. Hi Swagatam,

    May i know if the connection of t1 and t2 is correct? The drain of t2 connected to source of t1?

    Regards,

    ReplyDelete
    Replies
    1. Thanks, Good observation!

      No it's not correct, the sources should be made common and connected to ground and the drains should go to the taps of the transformer...I'll have to correct the diagram one more time...I'll do it soon hopefully.

      Delete
  16. Hi Swagatam,

    to get the 1KHz frequency for the value of R1,R2 and C1. what would be the duty cycle?

    Regards,

    ReplyDelete
    Replies
    1. good question! I think it should be preferably 50%, actually I am not very sure, will need to be investigated deeply.

      Delete
    2. Hi Swagatam,

      This is what i got in my 555 calculator:

      Frequency: 1kHz
      Duty Cycle: 50%
      Period (T) = 1 Milliseconds
      Mark = 500 Microseconds
      Space = 500 Microseconds

      C1 = 10 Nanofarrads

      R1 = 7.143 Kilohms
      R1 Preferred Value = 6.8 Kilohms

      R2 = 71.429 Kilohms
      R2 Preferred Value = 68 Kilohms

      what about the testing of this circuit?

      Regards,
      Mike L

      Delete
    3. Thanks Mike!

      That looks neat.

      testing may be done just like an ordinary inverter by initially keeping the TR2 output disconnected with grid mains.

      Once the waveforms, frequency and power are confirmed using appropriate equipment, the output may be connected to the mains with correct polarity.

      Delete
  17. Hi Swagatam,

    what about the testing of the new circuit? is it the same with the first circuit?

    Regards,

    ReplyDelete
  18. Hi Swagatam, great project, I tried the schematic on a breadboard and it worked so far. I changed T2 drain/sorce pins, used IRF740PbF Mosfets and 15VA toroidal TR2. I used a bench power supply as a DC source and went up to 5VDC/0.04A, which produced a 80VAC. Didn't go any higher as the noise levels went up (around 0.8kHz). Also, I did not connect TR2 to TR1 as I have no oscilloscope to confirm wave form and phase. R1 was 6.8k, R2 68k, C1=10n and R7 was 1k (it wasn't mentioned). In your prev. schematics you used capacitors beteween R5 and T1 and (R6 and T2). Could this filter out the 0.8-0.9kHz noise from the transformer TR2? Also, would you suggest that running the timer from a stabilised power source like 78L12 could reduce the noise while feeding in the control frequency through an optical coupler? Could an optical coupler provide both frequency and amplitude data? Thanks for your advise. Br, Selim

    ReplyDelete
    Replies
    1. Hi Salim,

      Without an oscilloscope it would be quite dangerous to go head with this circuit...... for reducing the noise you may try increasing the frequency to above 20 kHz by reducing he value of C1.

      Regards.

      Delete
  19. Hi Swagatam,

    is there any way to check if LM556 is working?
    i built this circuit but i got a low output voltage to tr2.

    Regards,
    Mike L

    ReplyDelete
    Replies
    1. Hi Mike,

      Since the output is a PWM, it cannot be checked with a DMM, you will have to incorporate an oscilloscope.

      what output are you getting?

      Regards.

      Delete
    2. Hi Swagatam,

      i only got 6vac...

      i will try to find first a oscilloscope to test it again.

      Thanks and Regards,
      Mike L

      Delete
    3. Hi Mike,

      6V at the output of the transformer or at the output of the IC??

      Delete
    4. Hi Swagatam,

      6v at the output of tr2.

      Regards,
      Mike L

      Delete
    5. Hi Mike,
      check the voltage at the "PWM out" of the IC.

      Delete
    6. Hi Swagatam,

      I still dont have an oscilloscope. Can it be tested with the DMM? What woulb be the output voltage of the ic?

      Regards,

      Delete
    7. yes, check the voltage with a DMM at the output of the IC....

      Delete
    8. what is the voltage at the output of the IC?

      Delete
    9. I would like to know it from you....

      Delete
  20. hi swagatam !
    great project !
    we want to know if is posible to get 240V and 50 hz output

    thanks
    regards ! !

    ReplyDelete
    Replies
    1. Thanks! since the input is synchronized with the grid voltage, the frequency would be followed accurately..... wattage can be upgraded by using appropriately rated mosfets

      Delete
  21. Those who are asking most of these newbie questions do not know enough to do this safely. Many dangers lurk here, electrocution, fire, damage to connected equipment, etc. Great project, but seriously not one to undertake without a good understanding of whats going on!

    ReplyDelete
  22. Hi Swagatam, could you please help me understand the function of T3/4. I know it's important that both FET-gates should not be positive at the same time. Using breadboard, and iCircuit simulator, I always got the same results. Only one FET was operating (10V pulse at gate) and the other one at 0.8V pulse at gate, not enough to open the gate (>2V) . So I tried using 3 NOR gates of a 4001 and it switched sides at 50Hz. Was this the purpose of T3/4 or did you put them in to prevent the FETs T1/2 conducting at the same time only? BTW, can I contact you by email?
    Regards,
    Selim
    ps disregard prev msg

    ReplyDelete
    Replies
    1. Hi Selim,

      That's correct, T3/T4 has been introduced so that the mosfets conduct alternately and never together.

      Delete
  23. Thanks, Swagatam.

    Somehow T3/4 won't work, but with 4001 it will alternate at 50Hz.

    On iCircuit (iPad) and on the breadboard, I get at the gates: T1=+12.2V, and T2=+0.845V PWM-signals, same phase, not alternating between T1/2.

    So effectively only one side of the primary winding coil (6V-0-6V) is energised. Leaving T3/4 running on the breadboard, using 2.5VDC/0.05A input, I get around 90VAC at 820-870Hz (wobbling at around 50Hz, I think).

    Using NORs from 4001, I can get it alternated in sync between T1/2, now here comes the next question.
    On iCircuit, I noticed that the positive wave gets PWM modulated properly where as the negative wave (or the missing bit/flat line between 2 positive waves) is only PWM modulated as a series of short pulses (no width/no power). The output would be distorted, such as larger positive waves vs. smaller negative waves. Is there a way to capture the negative side as well? Maybe another NE555/6 could do this job using the same 1kHz chopper.

    Please keep this project up. It seems like it could work well.
    Regards

    ReplyDelete
    Replies
    1. Thanks for the observations and suggestions Selim!

      OK, If cmos gates work better we can use them instead of the transistors, no issues.

      In the first diagram I tried to take care of the negative wave forms also but in the improved version I completely forget about it.

      We'll have to incorporate another IC555 for this, and feed the two mosfets with separate signals from the two 555 ICs.

      I'll try to present the finalized design soon...

      Regards.

      Delete
    2. Hi Swagatam, Any update on promising finalized design diagram with another incorporated IC555?
      I was building one when your post came out, so now I'm waiting. Please!

      Delete
    3. Hi Kevin,

      The design was updated a long time ago, an additional 555 was not felt necessary as the negative half cycles could be simply derived by using s bridge rectifier network.

      please refer to the second last diagram which hopefully satisfies all the conditions.

      Delete
    4. ....sorry, I misspelled you name.

      Delete
  24. Hi Swagatam, I managed to pickup both waves, and PWMed them and then run through 4013 to divide the 100Hz by two. The results look good on iCircuit. Both wave halves are PWMed at 9kHz and alternated on T1/2 evenly. The secondory winding phase in-sync with control input. I'll email you the pics later today. Two 4001 can be used iso 4013, but would require more wiring on the breadboard is needed. I think two 555s could do a much better job. I haven't figured out how to feed a 555 with a negative wave yet.
    Regards,
    Selim

    ReplyDelete
    Replies
    1. Hi Selim,

      Thanks! it would be interesting to see how you derived both the halves of the AC for the required sync. will wait for the images.

      Delete
  25. Hi Swagatam,

    I got a little concern about what would happen if this circuit was disconected from the mains but still getting a DC input from say a solar panel/turbine. The way i see it is that TR2 will keep trying to feed TR1 and the whole circuit will go out of control resulting in the end of the plug being live. A normal mains failure will most likely drown TR2 out due to not being able to feed a whole city !!.
    Hope i am missing something here.

    Best regards and keep up this project.

    ReplyDelete
    Replies
    1. Thank you for the interesting observation!

      However if TR2 drowns, TR1 would also stop producing the required data supply to the circuit, and the whole system would stall:-)

      But yes your point is noteworthy, and the issue should be checked practically for a reliable solution.

      Regards.

      Delete
  26. Hi Swagatam,

    What is the value of the zener diode?

    Maybe we can put a relay to cut the source coming from tr2.

    Regards,
    Mike L

    ReplyDelete
    Replies
    1. Hi Mike,

      It can be anything from 3V to 8V....we just want to delay the switching fractionally between the transistors.

      Yes a relay would be a good idea for correcting the above issues.....

      Thanks.

      Delete
  27. Hi Swagatam,

    what is the value of zener diode?

    R1,R2 and C1? what is the frequency to be use?

    Regards,
    Mike L

    ReplyDelete
    Replies
    1. Hi Mike,

      You will have to calculate them using any online 555 calculator software.

      Regards.

      Delete
    2. Is it 1kHz or 20kHz?

      Delete
    3. It has to be a high frequency, the figure does not matter...

      Delete
    4. I am using 1K (R7) resistor and a 5.6 volts zener.

      Delete
    5. That should be OK, the idea is to keep the transistor conductions well isolated, and in an alternate manner.....the zener diode makes sure that the transistor conductions do not overlap (as far as I thing).

      Delete
  28. Hi Swagatam,

    what is wrong if the voltage coming out to the PWM out of IC 556 is not stable? i measured it from 10V and then going down to 3V.
    Pin#3 (not connected)output is stable to 10V.

    Regards,
    Mike L

    ReplyDelete
    Replies
    1. Hi Mike,

      The output PWM should vary with the control voltage......

      Delete
  29. hi i also trying to do one
    need to know about that
    can i send it to u

    ReplyDelete
  30. http://imageshack.us/photo/my-images/694/img3181oi.jpg/
    hi this is the link for my diagram
    regards dumidu

    ReplyDelete
  31. can be used for recharge baruti.themigambo @ yahoo.co

    ReplyDelete