Wednesday, February 27, 2013

Make this Simple Delay ON Timer Circuit - Application Note Included

The post explains a simple delay ON circuit which allows the connected load at the output to be switched ON with some predetermined delay after power switch ON.


The explained circuit can be used for all applications which calls for an initial delay ON feature for the connected load after the mains power is switched ON.

The shown diagram is pretty straightforward yet provides the necessary actions very impressively, moreover the delay period is variable making the set up extremely useful for the proposed applications.

The functioning can be understood with the following points:

Assuming the load which requires the delay ON action being connected across the relay contacts, when power is switched ON, the 12V DC passes via R2 but is unable to reach the base of T1 because initially, C2 acts as a short across ground.

The voltage thus passes through R2, gets dropped to relevant limits and starts charging C2.

Once C2 charges up to a level which develops a potential of 0.3 to 0.6V (+ zener voltage) at the base of T1, T1 is instantly switched ON, toggling T2, and the relay subsequently....finally the load gets switched ON too.

The above process induces the required delay for switching ON the load.

The delay period may be set by appropriately selecting the values of R2 and C2.

R1 ensures that C2 quickly discharges through it so that the circuit attains the stand by position as soon as possible.

D3 blocks the charge from reaching the base of T1.







Parts List

R1 = 610K
R2 = 330K
R3= 10K
R4 = 1K
D1 = 3V zener diode
D2 = 1N4007
D3 = 1N4148
T1 = BC547
T2 = BC557
C2 = 33uF/25V
Relay = SPDT, 12V/400 Ohms


Application Note

Let's learn how the above circuit becomes applicable for solving the following presented issue by one of the keen followers of this blog, Mr. Nishant.


Hello Sir,
I have a 1KVA automatic voltage stabilizer.It has one defect that when it is switched on, very high voltage is outputted for about 1.5s (therefore cfls and bulb got fused frequently) after that the voltage becomes OK. I have opened the stabilizer it consist of an auto-transformer,4 24V relay each relay connected to a separate circuit(each consisting of 10K preset,BC547,zener diode,BDX53BFP npn darlington pair transistor IC,220uF/63v capacitor,100uF/40V capacitor ,4 diodes and some resistors).These circuits are powered by a step down transformer and output of these circuit are taken across corresponding 100uF/40V capacitor and fed to corresponding relay.What to do in order to tackle the problem.please help me.Hand drawn circuit diagram is attached.



Solution:

The problem in the above circuit might be due to two reasons: one of the relays is switching ON momentarily connecting the wrong contacts with the output, or one of the responsible relays is settling down with the correct voltages a little while after power switch ON.

Since there are more than one relay, tracing out the fault and correcting it can be a bit tedious......the circuit of a delay ON timer explained in the above article could be actually very effective for the discussed purpose.

The connections are rather simple.

Using a 7812 IC, the delay timer can be powered from the existing 24V supply of the stabilizer.

Next, the delay relay N/O contacts may be wired in series with the stabilizer output socket wiring.

The above wiring would instantly take care of the issues as now the output would switch after some time during power witch ONs, allowing enough time for the internal relays to settle down with the correct voltages across their output contacts.

20 comments:

  1. Hello Sir,
    1.What is the power rating of each resistor?

    2.Will SPDT 12V relay,7A would work?Please specify the current rating?please check this link is it ok?
    http://evelta.com/index.php?route=product/product&path=158_81&product_id=58

    3.Can I power the above circuit with the same 12 0 12 step down transformer which is already there in the stablizer used to power 4 above hand drawn circuits.

    If yes then how?
    connecting 24v ac to bridge rectifier (using 1N4007) then a filter capacitor(please tell the best value preferred ), also tell the preferred value for filter capacitor(ceramic or electrolytic?) to be connected at input and output of 7812,Is this power supply will comfortably run the delay circuit?

    ReplyDelete
    Replies
    1. Hello Nishant

      1) All resistors are 1/4 watt CFR

      2) Yes the shown relay will work.

      3) you will have to use the 0-12 tap and connect a bridge rectifier/capacitor(1000uF/25V) with it and then the output would become OK for the above circuit.

      Alternatively you may use a 7812 IC and feed its input with the existing 24V DC...the output of the 7812 would then become applicable for the above circuit.

      Delete
  2. hello sir,
    i tried ur above circuit with 2 transistor in simulation software but its not working.......plz help me out....

    ReplyDelete
    Replies
    1. helo rocky, try it practically, it will work.

      Delete
  3. I have tryed it practically and mine doesen't Work.

    ReplyDelete
    Replies
    1. I have tried this circuit and it works just as explained.

      Delete
  4. hi mr swagatam,

    I am graduating engineering student can u help me to have a piece of idea for what i am going to invent as my theses please?
    thank you more power

    ReplyDelete
  5. hi mr swagatam please help me i am going to do a project for my theses i am just run out of time please provide me an idea to have a starting point in doing a ece project as my theses thanks. more power

    ReplyDelete
    Replies
    1. Hi Sandy, It will be difficult for me to suggest any particular project, you can choose any one from this blog, it has plenty neat stuffs of all levels.

      Delete
  6. What is the formula for determining the delay time from R2 and C2? I need about 1 second of delay. Thank you

    ReplyDelete
    Replies
    1. the formula is complicated, Google "RC time delay formula", you'll get an idea

      Delete
    2. ...you can set it with some trial and error.

      Delete
  7. sir! if want to use this circuit with two relays, how to connect it?
    i have an 15v 150mA adapter can i use it to supply this circuit? if can, do i need a regulator or 12v zener to step down it?

    ReplyDelete
    Replies
    1. you can connect the relay coils in parallel in the above circuits.
      you can connect 15V directly, no need to step it down.

      Delete
  8. The circuit works fine, thanks for the article. I have a requirement where I need delay ON and delay OFF. The required delays are very small, about 10 ms. How can I modify the above circuit to achieve ON and OFF delays?

    ReplyDelete
    Replies
    1. connect another capacitor right across the base and ground of T1, let's call it C1.

      Dimension C1/C2 for getting the 10ms delay,

      Delete
  9. hi swagatam.
    i want a delay of 3-8 seconds. will it work? by the way what are is the time delay of this circuit in this configuration?
    i want to run this directly on 220V. but dont want to use transformer or power supply. can you please give me a link or suggest me a capacitor diode based simplest power supply as an addon.
    thanks. waiting for your reply as you have not replied me before.

    ReplyDelete
    Replies
    1. Hi Muhammad, any delay between 1 second and 1 minute can be achieved from the above circuit by varying R2/C2 accordingly.

      you can try the following transformerless power supply:

      http://1.bp.blogspot.com/-9MKa1nQydEY/U6fgPJheSeI/AAAAAAAAHVA/FQbUQOL1qa8/s1600/simple+1+watt+LED+driver+circuit.png

      Remove the shown LEDs, and use the transistor emitter as the positive supply for the delay circuit. You can also remove the 56 ohm resistor, it's not required.

      Delete
  10. sir,
    i want to use above circuit work for 10 min
    is it possible by changing R2 and C2????????

    ReplyDelete
    Replies
    1. yes it's possible by increasing R2/C2 and also by increasing D1 voltage rating

      Delete

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Readers are advised to proceed with the construction of the presented circuits only after understanding the concepts from the core. Not adhering to this can lead to failures and frustrations.